Tuesday, 24 June 2008
Gawk Print Last Field
gawk script to print the last field of each line:
gawk -F <delimiter> "{ print $NF }".
-F defines the separator in the command line, otherwise you would prepend "BEGIN { FS=<delimiter> }".
NF is the number of fields in a line and $n is the value of the n'th field, so $NF outputs the last field.
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Labels: GnuWin
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posted by Kam-Hung Soh @ 11:27 AM
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